The general solution of sin x=sin α, α ϵ [−π2,π2] is – InterviewSolution

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1.	The general solution of sin x=sin α, α ϵ [−π2,π2] is
Answer» The general solution of $s i n x = s i n α, α ϵ [- \frac{π}{2}, \frac{π}{2}]$ is

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