InterviewSolution
Saved Bookmarks
| 1. |
The geometric mean of the minimum and maximum values of the distance of point (-7, 2) from the points on the circle `x^(2)+y^(2)-10x-14y-51=0` is equal toA. `2sqrt(11)`B. 13C. `5sqrt(5)`D. 12 |
|
Answer» Correct Answer - A Let C be the centre of the given circle and r be its radius. The coordinates of C are (5, 7) and `r=5sqrt(5)`. The maximum and minimum values of the distances of point P(-7, 2) from the points on the given circle are (CP + r) and (CP-r) respectively. We have, `CP=sqrt((5+7)^(2)+(7-2)^(2))=13` Hence, required geometric mean `=sqrt((13+5sqrt(5))(13-5sqrt(5)))=sqrt(169-125)=2sqrt(11)` |
|