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The geometry of [Ni(CO)_(4)] and [Ni("PP"h_(3))_(2)Cl_(2)] are |
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Answer» both square planar `Ni^(0)(Z=28):3d^(8)4s^(2)` Since CO is striong field ligand , it forces electrons to pair up and thus `sp^(3)`hybridisation takes place which results in tetrahedral geometry.  In `[Ni("PP"h_(3))_(2)Cl_(2)]` oxidation station fio `Ni=+2`. This COMPLEX contsins weak field lignad `(Cl^(-))` as well as strong field `("PP"h_(3))` . Weak field ligand favours tetrahderal geometry and strong field ligand favours square planar geometry. Hence this compound is borderline between these two geometries. But due to steric effect of two larger `"PP"h_(3)` ligands LESS crowded tetradehral geometry is favoured 
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