1.

The Gibbs energy for the decomposition of `FeO` at `600^@ C` is as follows `FeO rarr Fe + (1)/(2) O_2 Delta_r G = 856 kJ//"mole"` the potential difference needed for electrolytic reduction of `FeO` at `600^@ C` is at least.A. `-3.6 V`B. `-4.73 V`C. `-5.2 V`D. `-4.42 V`

Answer» Correct Answer - D
`Delta G = - nFE`
`E = (-856 xx 10^3)/(2 xx 96500)`
`E = -4.43 V`.


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