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The Gibbs energy for the decomposition of `FeO` at `600^@ C` is as follows `FeO rarr Fe + (1)/(2) O_2 Delta_r G = 856 kJ//"mole"` the potential difference needed for electrolytic reduction of `FeO` at `600^@ C` is at least.A. `-3.6 V`B. `-4.73 V`C. `-5.2 V`D. `-4.42 V` |
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Answer» Correct Answer - D `Delta G = - nFE` `E = (-856 xx 10^3)/(2 xx 96500)` `E = -4.43 V`. |
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