InterviewSolution
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InterviewSolution
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the given figure, ABCD is a rectangle of dimensions 21 cm x 14icircle is drawn with BC as diameter. Find the arof the shaded region in the figure.21 cmimeter14 cm10 |
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Answer» Area of the shaded region= area of rectangle-area of semicircle =l*b - (pi*r^2)/2 =21*14 - (pi*7^2)/2 =294 - (22/7*49)/2 =294 - 22*7/2 =294 - 77 =217 cm^2 answerperimeter of shaded region = perimeter of rectangle- perimeter of semicircle =70 - 22 =48 cm |
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