The graph between two temperature scales A and B is shown in figure. Between upper fixed point and lower fixed point there are 150 equal division on A and 100 on scale B. The relationship for conversion between the two scales is given by

The graph between two temperature scales A and B is shown in figure. B

1.	The graph between two temperature scales A and B is shown in figure. Between upper fixed point and lower fixed point there are 150 equal division on A and 100 on scale B. The relationship for conversion between the two scales is given by
Answer» `(t_(A)-180)/(100)=(t_(B))/(150)` `(t_(A)-30)/(150)=(t_(B))/(100)` `(T_(B)-180)/(150)=(t_(A))/(100)` `(t_(B)-40)/(100)=(t_(A))/(180)` Solution :From graph, least POINT on scale A is `30^(@)C` and peak point is `180^(@)`. For scale B, least point is `0^(@)` and peak point is `100^(@)`. `:.` RELATION for conversion of temperature of TWO scales, `(t_(A)-A" least point on A")/("No. of marks on A")=(t_(B)-B" least point on B")/("No. of marks on B")` `(t_(A)-30)/(150)=(t_(B)-0)/(100)` `:.(t_(A)-30)/(150)=(t_(B))/(100)`