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The gravitation force exerted on rocket a time toheight h from the surface of earth is 1/3 time to the gravitation force exerted at the surface of sea. Then obtain the relation between h and R_e(radius of earth). |
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Answer» SOLUTION :`IMPLIES (GM_em)/((R_E+H)^2)=1/3((GM_em)/r^2)` `:. (R_e+h)^2 =3R_e^2` `:. R_e + h = SQRT3 = 1.732 R_e` `:. h = 0.732 R_e` |
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