1.

The gravitation force exerted on rocket a time toheight h from the surface of earth is 1/3 time to the gravitation force exerted at the surface of sea. Then obtain the relation between h and R_e(radius of earth).

Answer»

SOLUTION :`IMPLIES (GM_em)/((R_E+H)^2)=1/3((GM_em)/r^2)`
`:. (R_e+h)^2 =3R_e^2`
`:. R_e + h = SQRT3 = 1.732 R_e`
`:. h = 0.732 R_e`


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