The gravitational field in a region is given by vecE = (2hati+3hatj) N/Kg. The workdone by the field when the particle is moved on the line 3y + 2x = 5

The gravitational field in a region is given by vecE = (2hati+3hatj) N

1.	The gravitational field in a region is given by vecE = (2hati+3hatj) N/Kg. The workdone by the field when the particle is moved on the line 3y + 2x = 5
Answer» Solution :`vecE=2hati+3hatj` The FIELD is represented as Slope `m_1 = Ttantheta_(1)=3//2` The line 3Y + 2X = 5 can be represented as Slope `m_2=Tantheta_(2)=-2//3` `m_(1)xxm_2=-1` Since, the DIRECTION of the field and displacement are PERPENDICULAR the workdone by the field on the particle is zero.