Saved Bookmarks
| 1. |
The gravitational field in a region is giveny by vecE = (2hati +3hatj) N/kg. The workdone by the field when the particle is moved on the line 3y+2x=5 |
|
Answer» SOLUTION :`vecE=2hati+3hatj` The FIELD is represented as Slope `m_1=Tan theta_1=3//2` The line 3y+2x=5 can be represented as Slope `m_2=Tan theta_2=-2//3` `m_1xxm_2=-1` Since, the direction of the field and displacement are perpendicular the WORKDONE by the field on the PARTICLE is zero.
|
|