1.

The gravitational field in a region is giveny by vecE = (2hati +3hatj) N/kg. The workdone by the field when the particle is moved on the line 3y+2x=5

Answer»

SOLUTION :`vecE=2hati+3hatj`
The FIELD is represented as
Slope `m_1=Tan theta_1=3//2`
The line 3y+2x=5 can be represented as Slope
`m_2=Tan theta_2=-2//3`
`m_1xxm_2=-1`
Since, the direction of the field and displacement are perpendicular the WORKDONE by the field on the PARTICLE is zero.


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