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The gravitational force between two bodies is 1 N. If the distance of these two bodies is doubled, what will be the force of attraction between them ? |
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Answer» SOLUTION :`IMPLIES F_(1) prop 1/(r_1^2) and F_(2) prop 1/r_2^2` `:. F_2/F_1 = (r_1/r_2)^2 =(R/(2R))^2=1/4` `:. F_(2) = F_(1)/4 =1/4 = 0.25 N` |
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