1.

The gravitational force between two stones each of mass 1 kg placed at a distance of Im in vaccum is .........

Answer»

ZERO
`6.675 xx10^(-5) N`
`6.675 xx10^(-11) N`
`6.675 xx10^(-8) N`

Solution :`implies F = G (m_1m_2)/r^2 =(6.67xx10^(-11)(1)(1))/((1)^2)`
`= 6.67xx10^(-11) N`


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