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The gravitational potential energy of a body of mass m at the earth's surface is mgR_e . Its gravitational potential energy at a height R_efrom the earth's surface will be ..... (Here R_eis the radius of earth) |
Answer» <html><body><p>`-2 mg R_e` <br/>`2 mg R_e`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/2 mg R_e`<br/>`-1/2 mg R_e`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> DeltaU = U_(2) - U_1 = (<a href="https://interviewquestions.tuteehub.com/tag/mgh-1095458" style="font-weight:bold;" target="_blank" title="Click to know more about MGH">MGH</a>)/(1+(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)/(R_e) ) = (mgh)/(1+R_e/R_e) = (mgR_e)/2` <br/> `:. U_2 - (-mg R_e) = (mgR_e)/2` <br/> `:. U_2 =-1/2 mg R_e`</body></html> | |