1.

The gravitational potential energy of a rocket of mass 200kg at a height of 10^(7)m from the earth's surface is 10^(9)s. The potential energy of the rocket at a height of 26.4xx10^(6)m from the surface of earth is:

Answer» <html><body><p>`-1.5xx10^(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)J`<br/>`-0.5xx10^(9)J`<br/>`-2.5xx10^(9)J`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/2xx10-1840192" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX10">2XX10</a>^(9)J`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>=-(GMm)/((R+h))""U'=-(GMm)/((R+h'))` <br/>`(U')/(U)=((R+h)/(R+h'))` <br/>`=((<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>.4+10)xx10^(6))/((6.4+26.4)xx10^(6))` <br/>`=(16.4)/(32.8)=(1)/(2)` <br/>`thereforeU'=-(U)/(2)=(-10^9)/(2)=-0.5xx10^(9)J`</body></html>


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