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The greatest height to which a man can throw a stone is h. What will be the greatest distance upto which he can throw the stone? |
Answer» Maximum height: H = \(\frac{u^2sin^2θ}{g}\) ⇒ Hmax \(\frac{u^2}{2g}\) = h(at θ = 90) Maximum range Rmax = \(\frac{u^2}{2g}\) = 2h |
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