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The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case is1. 252. 183. 154. None of the above |
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Answer» Correct Answer - Option 3 : 15 Concept The greatest number by which dividing a, b and c leaves the same remainder in each case = HCF of (a - b) and (b - c) Calculation The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case = HCF of (138 - 63) and (228 - 138) ⇒ HCF of 75 and 90 [138 - 63 = 75 and 228 - 138 = 90] ⇒ 15 Hence, the greatest number is 15. |
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