1.

The group of molecules having identical shape is:

Answer»

`PCl_(5)IF_(5), XeO_(2)F_(2)`
`BF_(3),PCl_(3),XeO_(3)`
`SF_(4),XeF_(4),C Cl_(4)`
`CIF_(3),XeOF_(2),XeF_(3)^(+)`

Solution :`CIF_(3) to ` HYBRIDISATION `=3+(1)/(2)[7-3]=5(sp^(3)d)`
`XeOF_(2) to` Hybridisation `=3+(1)/(2)[8-4]=5(Sp^(3)d)`
`XeF_(3)^(+) to` Hybridation `=3+(1)/(2)[8-2-1]=5(sp^(3)d)`
All MOLECULES have `sp^(3)`hybridzation and 2 lone pairs. HENCE all haveidentical (T-shape).


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