1.

The H-H bond energy is 430 kJ mol^(-1) and Cl-Cl bond energy is 240 kJ mol^(-1), DeltaH and HCl is -90kJ. The H-Cl bond energy is about

Answer»

180 kJ `mol^(-1)`
360 kJ `mol^(-1)`
213 kJ `mol^(-1)`
425 kJ `mol^(-1)`

Solution :The FORMATION of one mole of HCl can be represented as, `(1)/(2)(H-H)+(1)/(2)(Cl-Cl)toH-Cl,DeltaH=-90kJ`
Hence, for the reaction,
Heat evolved=heat evolved in bond formation-heat required for bond breaking
`therefore 90 kJ=[H-Cl" bond energy"]-((1)/(2)xx430+(1)/(2)xx240)`
`therefore(H-Cl" bond energy")=90+(215+120)=425" kJ "mol^(-1)`


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