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The [H^(+)] in a solution containing 0.1 M HCOOH and 0.1 M HOCN [Ka for HCOOH and HOCN are 1.8 xx 10^(-4) and 3.3 xx 10^(-4)] respectively will be |
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Answer» `7.13 xx 10^(-2) M` `underset((0.1-y))(HOCN)hArr underset((x+y))(H^(o+))+underset(y)(OCN^(o+))` `K_(HCOOH)= ([H^(+)][HCOO^(-)])/([HCOOH]) = 1.8 xx 10^(-4)` `K_(HOCN) = ([H^(+)][OCN^(-)])/([HOCN]) = 3.3 xx 10^(-4)` |
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