The (H+] of 0.008M Ba(OH), is (A) 1.25 x 10-12 M(B) 1.25 x 10-11 M(C) 6.25 X 10-13M(D) 1.0 x 10-7MA

The (H+] of 0.008M Ba(OH), is (A) 1.25 x 10-12 M(B) 1.25 x 10-11 M(C

1.	The (H+] of 0.008M Ba(OH), is (A) 1.25 x 10-12 M(B) 1.25 x 10-11 M(C) 6.25 X 10-13M(D) 1.0 x 10-7MA
Answer» B) 1.25 x 10-11 MExplanation:this is RIGHT ans plzz LIKE my ans