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The half cell reaction for rusting of iron are: `2H^(+)+2e^(-)+(1)/(2)O_(2)rarrH_(2)O(l), E^(@)=+1.23V` `Fe^(2+)+2e^(-)rarrFe(s), E^(@)=-0.44V` `DeltaG^(@)` (in KJ) for the reaction isA. `-76`B. `-322`C. `-161`D. `-152`. |
Answer» Correct Answer - B `E^(@)=1.23+0.44=1.67V` `DeltaG^(@)=-nFE^(@)` `=02xx96500xx1.67=-322310J` `=-322.31kJ` |
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