1.

The half-cell reactions of rusting of iron are 2H^(+)+1/2O_(2)+2etoH_(2)O," "E^(0)=+1.23V Fe^(2+)+2etoFe," "E^(0)=-0.44V DeltaG^(0) (in kJ) for the reaction is

Answer»

`-76`
`-322`
`-122`
`-176`

SOLUTION :`Fe+2H^(+)+1/2O_(2)TOFE^(2+)+H_(2)O,E_("cell")^(0)=1.67V`


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