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The half life for radio active decay of ""^14C is 5730 Y. An achaeological artefact contained wood had only 80% of the 14 C found in a living tree. Estimate age of the sample. |
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Answer» Solution :Decay constant (k) = `0.693/(t_1//2) = (0.693/5730yr^(-1))` RADIO active dacays follow FIRST order kinetics `t=2.303 / k log""([A]_0)/([A])` `k = 0.693/ 5730 yr^1[A]_0= 100%, [A] = 80%` `:.t = ((2.303 xx 5730)/0.693) xx log"" 100/80` `=((2.303 xx 5730 xx0.0969)/0.693)= 18 45` years. |
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