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The half-life for radioactive decay of ""^(14)C is 5730 y. An archaelogical artifact contained wood that had only 80% of the ""^(14)C found in living tree. Estimate the age of the sample. |
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Answer» Solution :RADIOACTIVE DECAY follows FIRST order kinetics. Decay constant `(K)=(0.693)/(t_(1//2))=(0.693)/(5730)"yr"^(-1)` `t=(2.303)/(k)log""([A]_(0))/([A])=(2.303)/((0.693//5730" yr"^(-1)))log""(100)/(80)=(2.303xx5730)/(0.693)xx0.0969" yr"=1845" years"` |
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