1.

The half-life of 2 sample are 0.1 and 0.4 seconds . Their respective concentration are 200 and 50 respectively . What is the order of reaction

Answer»

0
2
1
4

Solution :`t_(1//2) prop a^(1-N) IMPLIES (0.1)/(0.4) = ((200)^(1-n))/((50)^(1-n)) implies (1)/(4) [(4)/(1)]^(1-n) = [(1)/(4)]^(n-1)`
`implies (1)/(4^(1)) = (1)/(4^(n-1)) therefore n - 1 = 1 , n = 2`.


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