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The half-life of \(^{226}_{88}Ra\) is 1620 y. Find its decay constant in SI unit. |
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Answer» Data: T = 1620 y = 1620 × 365 × 8.64 × 104 S = 5.109 × 1010 s The decay constant of \(^{226}_{88}Ra\) is λ = \(\cfrac{0.693}T\) = \(\cfrac{0.693}{5.109\times10^{10}}\) = 1.356 × 10-11 s-1 |
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