1.

The half-life of a first order reaction [k=2.303/t log (a/(a-x))] is

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directly proportional to 'a'
inversely proportional to 'a'
independent of 'a'
proportional to (a - x)

SOLUTION :For a first order reaction
`k = (2.303)/(t) "LOG" (a)/(a-x) ` , when `t = t_(1//2) , x= (a)/(2)`
`therefore t_(1//2)= (2.303)/(k) "log" (a)/(a- (a//2))`
or `t_(1//2) = (2.303)/(k) "log" 2 = (2.303 xx 0.3010)/(k) = (0.693)/(k)`
i.e., Half LIFE of a1 order reaction is independent of INITIAL concentration 'a' of reactant.


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