1.

The half life of a radio isotope is four hours. If the initial mass of the isotope was 200 g the mass remaining after 24 hours undecayed is

Answer»

1.042 G
4.167 g
3.125 g
2.084g

Solution :`t_(1//2)=4` hr
No. of half lives in 24 hours,
`n=(24)/(4)=6`
`N_(0)=200` g
`N=(N_(0))/(2^(n))=(200)/(2^(6)) g`
`=(200)/(64)=3.125 g`


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