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The half life of a radio isotope is four hours. If the initial mass of the isotope was 200 g the mass remaining after 24 hours undecayed is |
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Answer» Solution :`t_(1//2)=4` hr No. of half lives in 24 hours, `n=(24)/(4)=6` `N_(0)=200` g `N=(N_(0))/(2^(n))=(200)/(2^(6)) g` `=(200)/(64)=3.125 g` |
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