1.

The half-life of decomposition of gaseous CH_(3)CHO at initial pressure of 365 mm and 170 mm of Hg were 420 sec and 880 sec respectively. The order of the reaction is:

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SOLUTION :`(t_(1//2)(1))/(t_(1//2)(2)) = [(p(2))/(p(1))]^(n-1)`
`880/410 = [364/170]^(n-1)`
`[2.14]^(1) = [2.14]^(n-1) , n-1 =1, n=2`


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