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The half-life of pononium is `140` days. After how many days. `16 gm` polonium will be reduced to `1 gm` (or `15 gm` will decay) ?A. 700 daysB. 280 daysC. 560 daysD. 420 days |
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Answer» Correct Answer - C We have `(N)/(N_(0))=((1)/(2))^(t//140)[thereforeN=No((1)/(2))^(n)andt=nt_(1//2)]` `1/16=((1)/(2))^(t//140)impliest/140=4(t_(1//2)=140days)` `impliest=560 days` |
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