1.

The half-life of the ratio element ._(83)Bi^(210) is 5 days. Starting with 20 g of this isotope, the amount remaining after 15 days is

Answer»

10 G
5 g
2.5 g
6.66 g

Solution :`n = (15)/(5) = 3, N = (N_(0))/(2^(n)) = (20)/(2^(3)) = (20)/(8) = 2.5 g`


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