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The half life period for the first order reaction XY_(2) rarr X+Y_(2) is 10 minutes . In what period would the concentration of XY_(2) be reduced to 10% of the original concentration ? |
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Answer» 33.2 min `= (0.693)/(10) = 0.0693 min^(-1)` `t = (2.303 )/(k) "LOG" ([A]_(0))/(0.1[A]_(0))` `= (2.303)/(0.0693)xx1= 33.2 ` |
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