1.

The half life period of a first order chemical reaction is 6.93 minutes . The time required for the completion of 99% of the chemical reaction will be ( log 2 = 0.301 ) :

Answer»

230.3 MINUTES
23.03 minutes
46.06 minutes
460.6 minutes

Solution :(C ) `k=(0.693)/(t_(1//2))`
`= (0.693)/(6.93)=0.1 "min"^(-1)`
`t= (2.303)/(k) "LOG" ([A]_(0))/([A])`
`= (2.303)/(0.1) "log" (100)/(1) `
`=(2.303xx2)/(0.1) = 46 .06 min`


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