1.

The half-life period of a first order reaction is 15 minutes. The amount of substance left after one hour will be

Answer»

one half
one FOURTH
one eighth
one sixteenth

Solution :Half-lives `=n=t/t_1= (1 HR)/(15 MIN)= 60/50=4`
AMOUNT lift `=[A]/[A]_0= 1/2^n= 1/2^4=1/16= [A]=[A]_0/16`


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