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The half - life period of a radioactive substance is 20 days. What is the time taken for `7//8^(th)` of its original mass to disintegrate ? |
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Answer» Half life period = 20 days In this problem, `(1)/(2^(n))=("Quantity remaining")/("Initial quantity")` `=(1)/(8)=(1)/(2^(3))` `therefore n =3` `therefore` Time taken to disintegrate `= n xx` Half life time `= 3xx20 = 60` days |
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