1.

The half life period of a reaction is 100 min . In 400 min the intitial concentration of 2.0 g willbecome :

Answer»

`0.25 g `
`0.75g`
`0.125g`
`0.1g`

Solution :(C ) `t_(1//2) = 100 ` mm
400 min =4 half LIFE PERIODS
Amount of substance LEFT = `(A_(0))/(2^(4))`
`(2.0)/(16) = 0.125 g `


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