1.

The half-life period of radioactive element is 140 days. After 560 days, 1 g of element will reduce to

Answer»

`1/2`G
`1/4`g
`1/8`g
`1/16`g

Solution : As we KNOW, `T= nxxt_(1//2)`
where, `t_(1//2)` = half-life period
`N=(T)/(t_(1//2))=(560)/(140)=4`
Now, `N_1=N_0(1/2)^n=1xx(1/2)^4=1/16g`


Discussion

No Comment Found

Related InterviewSolutions