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The half life period of Radon is 3.8 years. After how many days will one twentieth of Radon sample be left over ? |
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Answer» Solution :`lambda=(0.693)/(t_(1//2))=(0.693)/(3.8)=0.182day^(-1)` LET the initial AMOUNT of radon be `N_(0)` and amount left after `t` DAYS be `N` which is equal to `(N_(0))/(20)` `t=(2.303)/(lambda)log_(10).(N_(0))/(N)` `=(2.303)/(0.182)log_(10).(N_(0))/(N_(0)//20)=(2.303)/(0.182)log_(10)20` `=16.54` days |
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