1.

The half life period of the reaction : N_(2) O_(5) rarr 2NO_(2) +(1)/(2) O_(2) is 24 hrs at 30^(@) C. Starting with 10 g of N_(2) O_(5) how many grams of N_(2) O_(5) will remain after a period of 96 hours ?

Answer»

`1.25 g `
`0.63 g`
`1.75 g `
`0.5 g`

Solution :No. of half life PERIODS =4
Amount LEFT `=([A]_(0))/(2^(n))=(10)/(2^(4))=0.63 g `


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