1.

The half-life period of Uranium is 4.5 billion years. After 90 billion years, the number of moles of Helium liberated from the following nuclear reaction will be ._(92)U^(238) rarr ._(90)Th^(234) + ._(2)He^(4)

Answer»

0.75 mole
1.0 mole
11.2 mole
22.4 mole

Solution :`N = (N_(0))/(2^(n)) = N = (N_(0))/(2^(2)) = (1)/(4)`
`:.` CONVERTED moles `= 1 - (1)/(4) = (3)/(4) = 0.75`


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