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The half lives of two radioactive nuclides A and B are 1 and 2 min. respectively . Equal weights of A and B are taken separatelyand allowed to disintegrate for 4 min. What will be the ratio of weigths of A and B disintegrated ? |
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Answer» `1:1` T=4 min `t_(1//2)=1` min `N_(0)=x`(say) `n=4//1=4` `N=(N_(0))/(2^(n))=(x)/(2^(4))=(x)/(16)` A disintegrated `=x-(x)/(16)=(15x)/(16)` For B T=4 min `t_(1//2)=` 2 min `N_(0)=x` (say) `n=4//2=2` `N=(N_(0))/(2^(n))=(x)/(2^(2))` `=(x)/(4)` B disintegrated `x-(x)/(4)=(3x)/(4)` Ratio of A : B disintegrated `(15x)/(16):(3x)/(4)` or 5:4 |
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