The HCF and product of two numbers are 15 and 6300 respectively. The n – InterviewSolution

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1.	The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the numbers is1). 42). 33). 24). 1
Answer» Let the number be 15x and 15y, where X and y are co-prime.$ Since 15x $ $\times$ 15y = 6300$ $=> xy = \frac{6300}{15\times 15} = 28$ So, two pairs are (7, 4) and (14, 2)$ Hence the right option is [3].$

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