The heat capacity of a vessel is 300 cal .^(@)C^(-1) and the heat capacity of water contained in the vessel is also 300 cal .^(@)C^(-1). How much heat (in joules) is required to raise the temperature of water in the vessel by 126^(@)F?

The heat capacity of a vessel is 300 cal .^(@)C^(-1) and the heat capa

1.	The heat capacity of a vessel is 300 cal .^(@)C^(-1) and the heat capacity of water contained in the vessel is also 300 cal .^(@)C^(-1). How much heat (in joules) is required to raise the temperature of water in the vessel by 126^(@)F?
Answer» Solution :A rise in temeprature of `9^(@)C` is equal to a rise in temperature of `5.^(@)C`. `therefore`A rise in temperature of 126 `.^(@)F` is on the celsius SCALE EQUIVALENT to `126xx(5)/(9)=14xx5=70.^(@)C` quantity of heat required to RAISE the temperature of the vessel by `1.^(@)C=300cal` ltBrgt `therefore` Heat requried to raise its temperature by ltBrgt `70.^(@)C=70xx300=21000` cal. SIMILARLY heat required to raise the temperature of water by `70.^(@)C=70xx300=21000cal` `therefore` the TOTAL heat required `=(21000+21000)cal=42000cal` `=4200xx4.2=176.4kJ`