1.

The heat dissipated in a resistor can be obtained by the measurement of resistance, current and time. If the maximum error in the measurement of these quantities is 1%, 2% and 1% respectively, the maximum error in the determination of the dissipated heat is

Answer»

`4%`
`6%`
`(4)/(3)%`
`2%`

SOLUTION :Heat dissipated in a RESISTOR is given by `H= I^(2)Rt`
`:. (DeltaH)/(H)= 2(DeltaI)/(I)+ (DeltaR)/(R)+ (Deltat)/(t)`
For MAXIMUM percentage error,
`(DeltaH)/(H)xx100= 2(DeltaI)/(I)xx100+ (DeltaR)/(R) xx 100+(Deltat)/(t)xx100= 2 xx 2%+ 1%+ 1%= 6%`


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