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The heat evolved in the combustion of 112 L ofwater gas( CO + H_(2) in the ration of1:1 by volume) is ( Giventhat heats of combustion of H_(2) andCO are -241.8and -283 kJ mol^(-1) respectively. |
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Answer» `- 1414 . 0 kJ` `CO +(1)/(2) O_(2) rarr CO_(2), DeltaH = - 283kJ` Since, `H_(2)` and CO have same volume in the MIXTURE, THEREFORE, each `= 56L ` `DeltaH` for combustion of `56L ` of `H_(2)` `=-( 241.8) /( 22.40 xx56kJ = - 604.5 kJ` `DeltaH`for combustionof `56 L ` of CO `= - ( 283)/( 22.4) XX 56 kJ = - 707 .5 kJ` `:. `Total `DeltaH = - 604 + ( - 707.5) = -1312kJ` |
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