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The heat generated in a circuit is given by `Q = I^(2) Rt` , where `I` is current , `R` is resistance , and `t` is time . If the percentage errors in measuring `I , R , and t are 2% , 1% , and 1%` , respectively , then the maximum error in measuring heat will be |
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Answer» Correct Answer - `+- 6%` As `H = (I^2Rt)/(4.2)cal` `:. (DeltaH)/(H) = +-((2DeltaI)/(I) +(DeltaR)/(R )+(Deltat)/(t))` `=+-(2xx2% +1%+1%) =-6%` |
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