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The heat generated in a circuit is given by Q=I^(2)Rt, where I is current, R is resistance and t is time. If the percentage errors in measuring I,R and t are 2%,1% and 1% respectively, then the maximum error in measuring heat will be : |
Answer» <html><body><p>`2%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>%`<br/>`4%`<br/>`6%`</p>Solution :Here `Q=I^(2)Rt` <br/> `:.(dQ)/(Q)<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a>=2(<a href="https://interviewquestions.tuteehub.com/tag/di-431875" style="font-weight:bold;" target="_blank" title="Click to know more about DI">DI</a>)/(I)xx100+(dR)/(R)xx100+(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>)/(t)xx100` <br/> `2xx2%+1%+1%` <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> `(d)` is correct.</body></html> | |