1.

The heat of atomisation of PH_(3(g)) is 228 kCal mol^(-1) and that of P_(2)H_(2(g)) is 355 kCal mol^(-1). The energy of the P-P bond is (kn kCal)

Answer»

102
51
26
204

Solution :`PH_(3) rarr P + 3H, Delta H = 228`
`3(P- H) = 288 rArr (P - H) = 76`
`P_(2) H_(4) rarr 2P + 4H, Delta H = 355`
`(P-P) + 4(P-H) = 355`
`(P-P) = 355 -4 XX 76 = 51`


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