1.

The heat of atomization of PH_(3)(g) is 228 k cal mol^(-1) and that of P_(2)H_(4)(g) is 355 k cal mol^(-1). The energy of the P-P bond is

Answer»

102 K cal `mol^(-1)`
51 k cal `mol^(-1)`
26 k cal `mol^(-1)`
204 k cal `mol^(-1)`

Solution :Bond dissociation energy of `PH_(3)(g)`
= 228 k cal `mol^(-1)`
F - H bond energy `=(228)/(3)=76 " k cal mol"^(-1)`

Bond energy of 4(P-H)+(P-P)
`=355 k cal mol^(-1)`
or `4xx76+(P-P)=355k cal mol^(-1)implies51 k cal mol^(-1)`


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