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The heat of combustion of hydrocarbon C_(x)H_(y) is ''a'' calories and heat of formation of CO_(2) and H_(2)O are ''b'' and 'c' calories respectively then the heat of formation of hydrocarbon C_(8)H is (in calories) |
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Answer» `XA + YC -B` `Delta H_("comb") = x Delta H_(f_(CO_(2))) + (y)/(2) Delta H_(f_(H_(2)O)) - Delta H_(f_(C_(x)H_(y)))` `a= xb + (y)/(2) C- Delta H_(f_(C_(x)H_(y)))` `Delta H_(f_(C_(x)H_(y))) = xb + (yc)/(2) - a` |
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