1.

The heat of combustion of hydrocarbon C_(x)H_(y) is ''a'' calories and heat of formation of CO_(2) and H_(2)O are ''b'' and 'c' calories respectively then the heat of formation of hydrocarbon C_(8)H is (in calories)

Answer»

`XA + YC -B`
`xb + yc -a`
`b + xc - xa`
`xb + (y)/(2) c-a`

Solution :`C_(x) H_(y) + (x + (y)/(4)) O_(2) RARR xCO_(2) + (y)/(2) H_(2)O`
`Delta H_("comb") = x Delta H_(f_(CO_(2))) + (y)/(2) Delta H_(f_(H_(2)O)) - Delta H_(f_(C_(x)H_(y)))`
`a= xb + (y)/(2) C- Delta H_(f_(C_(x)H_(y)))`
`Delta H_(f_(C_(x)H_(y))) = xb + (yc)/(2) - a`


Discussion

No Comment Found