Saved Bookmarks
| 1. |
The heat of combustion of naphthalene (C_(10)H_(8)(s)) at constant volume was found to be - 5133 k J mol^(-1) . Calculatethe value of enthalpy change. |
|
Answer» `DELTAH = DeltaU + Deltan_(g) RT = - 5132 kJ mol^(-1) + ( - 2 mol) ( 8.314 XX 10^(-3)kJK^(-1) mol^(-1)) ( 298K)` `= -5133kJ mol^(-1)-5 kJ mol^(-1) = - 5138 kJ mol^(-1)` |
|